-45f=-12-33f^2

Solution for -45f=-12-33f^2 equation:

-45f=-12-33f^2

We move all terms to the left:

-45f-(-12-33f^2)=0

We get rid of parentheses

33f^2-45f+12=0

a = 33; b = -45; c = +12;
Δ = b2-4ac
Δ = -452-4·33·12
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-21}{2*33}=\frac{24}{66}
=4/11
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+21}{2*33}=\frac{66}{66}
=1
$